Home › Forums › Research chemical › Calculate the E^0 of the process
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Fe3+ + Y-4 ::equil:: FeY- Kf=1.3X1025
Fe2+ + Y+4 ::equil:: FeY2- Kf=2.1×1014
Calculate the E° for the process
FeY- + e- ::equil:: FeY2-
The answer is said to be 0.13 V.
My attempt since, the half reaction for the following is
Fe3+ + e- :rarrow: Fe2+ E°= +0.77 V
Fe2+ + e- :rarrow: Fe(s) E°= – 0.44 V
E1 = 0.77- (RT/Fn)ln 1/Kf
E1 = 0.77 – 0.0257/(3)(ln 1/ 1.3X1025) I put three here cuz there’s 3 electrons to form Fe(s)
E1 = 1.27 V
E2 = -0.44- (RT/Fn)ln 1/Kf
E2 =-0.44- 0.0257/(2)(ln 1/2.1×1014) put three here cuz there’s 2 electrons to form Fe(s)
E2 = -0.0162 V
If add or substract this answers I will still not get 0.13 V please help me DO I still have to use Nert’s Equation ?
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