Calculate the E^0 of the process

Home Forums Research chemical Calculate the E^0 of the process

This topic contains 1 reply, has 0 voices, and was last updated by  Natthe 10th May 2018 at 5:17 pm.

Viewing 1 post (of 1 total)
  • Author
    Posts
  • #4292

    Natthe
    Participant

    Fe3+ + Y-4  ::equil:: FeY-          Kf=1.3X1025

    Fe2+ + Y+4  ::equil:: FeY2-         Kf=2.1×1014

    Calculate the E° for the process
     FeY-  + e-   ::equil:: FeY2- 

     The answer is said to be 0.13 V.
      

    My attempt since, the half reaction for the following is
     Fe3+ + e-  :rarrow:   Fe2+   E°= +0.77 V
    Fe2+ + e-  :rarrow:   Fe(s)   E°= – 0.44 V 

    E1 = 0.77- (RT/Fn)ln 1/Kf

    E1 = 0.77 – 0.0257/(3)(ln 1/ 1.3X1025)   I put three here cuz there’s 3 electrons to form Fe(s)

    E1 = 1.27 V

    E2 = -0.44- (RT/Fn)ln 1/Kf

    E2 =-0.44- 0.0257/(2)(ln 1/2.1×1014)  put three here cuz there’s 2 electrons to form Fe(s)

    E2 = -0.0162 V

    If add or substract this answers I will still not get 0.13 V please help me :( DO I still have to use Nert’s Equation ?

Viewing 1 post (of 1 total)

You must be logged in to reply to this topic.